Безрасходная разгрузка накопленного кинетического момента инерционных исполнительных органов автономного космического аппарата на высокоэллиптической орбите - page 15

Безрасходная разгрузка накопленного кинетического момента …
15
12 0 1 61 3 25 2 25 0 1 1
2
1 1 0 65 2 2 1 3 3 4 4
) 16
(20 (35 2 )) 4 2 /
x K J k a k a k a k f
k k a k f k k f k f k
= − ω − ω +
+ + ω + + −
[ (5 −4
] [ ], (14)
2 2
13 25 0 1 1 0 1 3 0 2 3 4 4 2 8 ( ) 2 ( ) / K a k f k k f f k f k
= ω ω + ω − + [ − ] [ ], (15)
2 2 2
4 25 0 25 61 3 21 3
14
(12 5
,
k
f a a a k a k
K
ω + +
=
4 )
5 (16)
2 2
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2
0 1 65 3 25 2 0 1 3 3
2 2
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15 )) 16
2 (5 16 ) 4
(40 7 42 ) /
x K J k a k a k a a k f
k a k a f k k f
a k a k a a f k
= ω + + ω +
+ ω − − ω +
+ + ω ω
[2 (20 + (2
+ ] [2 ],
(17)
2 2 2
16 0 1 1 65 0 2 25 65
2
0 1 3 1 25 1 3 0 2 5 4
64 100 ))
20 80 ( ) 8 /
x K J k k a k a a
k k f a k f f k f k
= − ω ω − − +
+ ω + − ω +
[ (140 +285 +14
] [4 ], (18)
2 2
17 0 1 3 1 0 25 1 3 0 2 5 4 4 5 ( ) 20 ( ) 2 / K k k f a k f f k f k
= − ω ω + −ω + [ − ] [5 ], (19)
4 1 4 25 25 0
18
2 (8
,
k
f a a k k
K =
+ω )
(20)
2 2
21 61 1 25 1 0 21 0 65
2
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21 15 ))
5 (25 4 ) 15 ( 5 )
(100 7 10 )) /
x K J a k a k a a
k a a k f k k f a f
a k a k a a f k
= ω − ω + +
+ ω + ω + ω +
+ + ω +
[5 (20 + (8
−
(3 ] [4 ], (21)
2 2 2 4
22 0 1 1 65 0 21 0 61 0
2 2
21 0 1 6 5 61 1 0 6 7 7 8 ) 20 100 ( ) 5 /
x K J k k a a a
a k k f a k f f k f k
= ω ω ω ω
+ ω + ω − +
[ (140 +105 +256 −125 −147 −
−80 ] [4 ],
(22)
2 2
23 0 1 6 5 0 61 1 0 6 7 7 8 5 ( ) 20 ( ) / K k k f a k f f k f k
= ω ω + ω − + [4 − ] [4 ], (23)
2 2
8 21 61 3 6 25 61 0
24
(5 (25
,
f a a k a a k
K
k
+ ω
=
+ 3 ))
(24)
2 2
25 65 1 25 1 0 65 0
2 2 2 2 2
0 21 25 61 65 25 61 21 65
2
1 1 65 0 5 0 61 65 25 6 6 61 0 7
2 2
21 1 0 61 61 25 65 0 21 8
5 ( 15 21 ))
4 (12 5 7 ))
4 (5 ) (25 4 ) 10 )
(80 )) /
x K J a k a k a
a a a a a a a a
k k a f a a a k f a f
a k a a a a a f k
= ω − ω +
+ ω − − +
+ ω + ω − ω −
− − ω + ω
[4 (20 + (
(4 +3 −
(10 (7 +6 ) 9 (7 −16 ) ] [16 ], (25)
2
26 0 1 61 65 0 25 6 61 0 1 5
2
1 1 0 65 6 6 1 6 7 8 8
5 (5 ) 25
15 7 )) 5 /
x K J k a a a k a k f
k k a k f k k f k f k
= − ω ω + ω +
+ ω + +
[ (5 −7 )−4
(20 + ( − ] [4 ], (26)